Answer: 260.20:261.20
To find the total time taken to process 1000 instructions in the given 5-stage pipeline, we proceed as follows:
1. Determine the Clock Cycle Time (Tp)
The clock cycle time of a pipelined processor is determined by the maximum delay among all stages plus the inter-stage latch delay (d):
Tp=max(t1,t2,t3,t4,t5)+d
Given stage delays are 180,250,150,170, and 250 ns, and the latch delay is 10 ns:
Tp=max(180,250,150,170,250)+10=250+10=260 ns
2. Calculate Total Execution Time
The total time T required to execute N instructions in a k-stage pipeline (assuming no stalls) is given by:
T=(k+N−1)×Tp
Substituting the given values (k=5 stages, N=1000 instructions):
T=(5+1000−1)×260 ns
T=1004×260 ns=261,040 ns
3. Convert to Microseconds (μs)
Since 1 μs=1000 ns:
T=1000261,040 μs=261.04 μs
Thus, the time taken to process 1000 instructions is 261.04 microseconds.