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GATE EC question library

Practise GATE EC Electronics and Communication previous year questions free. Browse by subject, syllabus topic, year and question type, with answers and available solutions.

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Official PYQ2006Engineering MathematicsCalculusMCQ · 1 mark
As xx is increased from −∞-\infty to ∞\infty, the function f(x)=ex1+exf(x)=\frac{e^x}{1+e^x}
Official PYQ2006Networks, Signals and SystemsCircuit AnalysisMCQ · 1 mark
A two-port network is represented by ABCD\text{ABCD} parameters given by [V1I1]=[ABCD][V2−I2]\left[\begin{array}{c} \mathrm{V}_1 \\ \mathrm{I}_1 \end{array}\right]=\left[\begin{array}{ll} \mathrm{A} & \mathrm{B} \\ \mathrm{C} & \mathrm{D} \end{array}\right]\left[\begin{array}{c} \mathrm{V}_2 \\ -\mathrm{I}_2 \end{array}\right] if port-22 is terminated by …
Official PYQ2006Networks, Signals and SystemsCircuit AnalysisMCQ · 1 mark
In the two port network shown in the figure below, z12z_{12} and z21z_{21} are, respectively
Official PYQ2006Networks, Signals and SystemsCircuit AnalysisMCQ · 1 mark
The first and the last critical frequencies (singularities) of a driving point impedance function of a passive network having two kinds of elements, are a pole and a zero respectively. The above property will be satisfied by
Official PYQ2006Networks, Signals and SystemsCircuit AnalysisMCQ · 1 mark
A 2  mH2 \; \mathrm{mH} inductor with some initial current can be represented as shown below, where ss is the Laplace Transform variable. The value of initial current is
Official PYQ2006Networks, Signals and SystemsCircuit AnalysisMCQ · 1 mark
In the figure shown, assume that all the capacitors are initially uncharged. If Vi(t)=10u(t)\text{V}_i(t)=10 u(t) Volts, then V0(t)\text{V}_0(t) is given by
Official PYQ2006Control SystemsMCQ · 1 mark
Consider two transfer functions G1(s)=1s2+as+b and G2(s)=ss2+as+b\mathrm{G}_1(s)=\frac{1}{s^2+a s+b} \text{ and } \mathrm{G}_2(s)=\frac{s}{s^2+a s+b} The 3-dB3\text{-dB} bandwidths of their frequency responses are, respectively
Official PYQ2006Control SystemsMCQ · 1 mark
A negative resistance Rneg R_{\text{neg }} is connected to a passive network NN having driving point impedance Z1Z_{1} (s) as shown below. For Z2(s)Z_{2}(s) to be positive real,
Official PYQ2006Analog CircuitsDiode CircuitsMCQ · 1 mark
In the circuit shown below, the switch wa connected to position 11 at t<0t<0 and at t=0t=0, it is changed to position 22. Assume that yy the diode has zero voltage drop and a storage time tst_{s}. For 0<t≤ts,VR0 < t \leq t_{s}, \text{V}_{\text{R}} is given by (all in volts)
Official PYQ2006Electronic DevicesMCQ · 1 mark
The majority carriers in an nn-type semiconductor have an average drift velocity V\mathrm{V} in a direction perpendicular to a uniform magnetic field B.\text{B}. The electric field E\mathrm{E} induced due to Hall effect acts in the direction
Official PYQ2006Analog CircuitsDiode CircuitsMCQ · 1 mark
Find the correct match between Group 11 and Group 22 …
Official PYQ2006Electronic DevicesMCQ · 1 mark
A heavily doped nn-type semiconductor has the following data Hole-electron mobility ratio : 0.40.4 Doping concentration : 4.2×108  atoms/m34.2 \times 10^{8} \; \mathrm{atoms/m}^{3} Intrinsic concentration : 1.5×104  atoms/m31.5 \times 10^{4} \; \mathrm{atoms/m}^{3} The ratio of conductance of the nn-type semiconductor to that of the intrinsic semiconductor of same material and …
Official PYQ2006Analog CircuitsOp-amp CircuitsMCQ · 1 mark
For the circuit shown in the following figure, the capacitor CC is initially uncharged. At t=0t=0, the switch SS is closed. The voltage VCV_{C} across the capacitor at t=1t=1 millisecond is In the figure shown above, the OP AMP\text{OP AMP} is supplied with ±15 V\pm 15 \mathrm{~V} and the ground has been shown by the symbol ∇\nabla.
Official PYQ2006Digital CircuitsNumber RepresentationsMCQ · 1 mark
A new Binary Coded Pentary (BCP) number system is proposed in which every digit of a base-55 number is represented by tis corresponding 33-bit binary code. For example, the base-55 number 2424 will be represented by its BCP code 010100.010100. In this numbering system, the BCP code 100010011001100010011001 corresponds to the following number in base-55 …
Official PYQ2006Digital CircuitsCombinatorial CircuitsMCQ · 1 mark
An IO\frac{\mathrm{I}}{\mathrm{O}} peripheral device shown in Figure (b)(b) below is to be interfaced to an 80858085 microprocessor. To select the IO\frac{\mathrm{I}}{\mathrm{O}} device in the IO\frac{\mathrm{I}}{\mathrm{O}} address range D4H−D7H\mathrm{D} 4 \mathrm{H}-\mathrm{D} 7 \mathrm{H}, its chip-select (CS‾)(\overline{C S}) should be connected to …
Official PYQ2006Digital CircuitsSequential CircuitsMCQ · 1 mark
For the circuit shown in figure below, two 44-bit parallel-in serial-out shift registers loaded with the data shown are used to feed the data to a full adder. Initially, all the flip-flops are in clear state. After applying two clock pulses, the outputs of the fulladder should be
Official PYQ2006Digital CircuitsSequential CircuitsMCQ · 1 mark
Two D\text{D}-flip-flops, as shown below, are to be connected as a synchronous counter that goes through the following Q1Q0\mathrm{Q}_{1} \mathrm{Q}_{0} sequence 00⟶01⟶11⟶10⟶00⟶…00 \longrightarrow 01 \longrightarrow 11 \longrightarrow 10 \longrightarrow 00 \longrightarrow \dots The inputs D0D_{0} and D1D_{1} respectively should be connected as
Official PYQ2006Digital CircuitsComputer OrganizationMCQ · 1 mark
Following is the segment of a 80858085 assembly language program LXISP,EFFFH\text{LXISP,EFFFH} CALL 3000 H\text{CALL 3000 H} 3000H:LXIH,3CF4H3000 \mathrm{H}: \mathrm{LXIH}, 3 \mathrm{CF} 4 \mathrm{H} PUSH PSW\text{PUSH PSW} SPIH\text{SPIH} POP PSW\text{POP PSW} RET\text{RET} On completion of RET\text{RET} execution, the contents of SP\mathrm{SP} is
Official PYQ2006Digital CircuitsCombinatorial CircuitsMCQ · 1 mark
The point P\text{P} in the following figure is stuck-at-11. The output ff will be
Official PYQ2006Networks, Signals and SystemsContinuous-time SignalsMCQ · 1 mark
A signal m(t)m(t) with bandwidth 500 Hz500 \mathrm{~Hz} is first multiplied by a signal g(t)g(t) where g(t)=∑R=−∞∞(−1)kδ(t−0.5×10−4k)g(t)=\sum_{\mathrm{R}=-\infty}^{\infty}(-1)^{k} \delta\left(t-0.5 \times 10^{-4} k\right) The resulting signal is then passed through an ideal lowpass filter with bandwidth 1  kHz1 \; \mathrm{kHz}. The output of the lowpass filter would be