Official PYQ · 2006Set 1 · Q50Continuous-time SignalsMCQ1 mark

GATE EC 2006 Set 1 Q50 — Continuous-time Signals

A signal $m(t)$ with bandwidth $500 \mathrm{~Hz}$ is first multiplied by a signal $g(t)$ where
$g(t)=\sum_{\mathrm{R}=-\infty}^{\infty}(-1)^{k} \delta\left(t-0.5 \times 10^{-4} k\right)$
The resulting signal is then passed through an ideal lowpass filter with bandwidth $1 \; \mathrm{kHz}$ . The output of the lowpass filter would be

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Published 10 Oct 2026

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