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Official PYQ · 1994

GATE CS 1994 Q2.9 — Partial Orders and Lattices

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The Hasse diagrams of all the lattices with up to four elements are ________ (write all the relevant Hasse diagrams)
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Answer: 5

A lattice is a partially ordered set (poset) in which every pair of elements has a unique least upper bound (LUB or join) and a unique greatest lower bound (GLB or meet). Any finite lattice must have a unique least element (00) and a unique greatest element (11).

Let us find all non-isomorphic lattices with nn elements, where 1≤n≤41 \le n \le 4:

  1. For n=1n = 1: (1 lattice)
    • A single element: {a}\{a\}.
    • Hasse Diagram: A single vertex.
  2. For n=2n = 2: (1 lattice)
    • A chain of 2 elements: 0<10 < 1.
    • Hasse Diagram: Two vertices connected by a single vertical edge.
  3. For n=3n = 3: (1 lattice)
    • A chain of 3 elements: 0<a<10 < a < 1.
    • Hasse Diagram: Three vertices connected linearly in a single vertical path.
  4. For n=4n = 4: (2 lattices)

    Let the elements be {0,a,b,1}\{0, a, b, 1\}, where 00 is the bottom and 11 is the top. The middle elements aa and bb can be related in two ways:

    • Case 4a (Chain): aa and bb are comparable (e.g., 0<a<b<10 < a < b < 1). This forms a linear chain of 4 elements.
    • Case 4b (Diamond): aa and bb are incomparable. Here, a∧b=0a \wedge b = 0 and a∨b=1a \vee b = 1. This forms a diamond-shaped lattice.

Summing these up, the total number of distinct Hasse diagrams for lattices with up to 4 elements is:

1 (for n=1)+1 (for n=2)+1 (for n=3)+2 (for n=4)=51 \text{ (for } n=1) + 1 \text{ (for } n=2) + 1 \text{ (for } n=3) + 2 \text{ (for } n=4) = 5

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