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Official PYQ · 1994

GATE CS 1994 Q1.8 — Combinational Circuits

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The logic expression for the output of the circuit shown in figure below is:

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Answer: B

To find the logic expression for the output of the given circuit, we can trace the output of each gate step-by-step from the inputs:

  1. NAND Gate: The inputs are AA and BB. The output of this gate is: G1=AB‾G_1 = \overline{AB}
  2. First AND Gate: The inputs are the output of the NAND gate (G1G_1) and CC. The output of this gate is: G2=G1⋅C=(AB‾)CG_2 = G_1 \cdot C = (\overline{AB})C
  3. Second AND Gate: The inputs are CC and DD. The output of this gate is: G3=CDG_3 = CD
  4. OR Gate (Final Output): The final output combines the outputs of the two AND gates (G2G_2 and G3G_3): Y=G2+G3=(AB‾)C+CDY = G_2 + G_3 = (\overline{AB})C + CD

Now, we simplify the expression using De Morgan's Law (AB‾=A‾+B‾\overline{AB} = \overline{A} + \overline{B}):

Y=(A‾+B‾)C+CDY = (\overline{A} + \overline{B})C + CD Y=A‾C+B‾C+CDY = \overline{A}C + \overline{B}C + CD

This matches the expression given in Option B.

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