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Official PYQ · 2011

GATE CS 2011 Q15 — Sequential Circuits

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The minimum number of D\text{D} flip-flops needed to design a mod-258 counter is

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Answer: A

A modulo-NN (or mod-NN) counter goes through NN unique states. To represent these NN states, we need nn flip-flops such that the total number of possible states, 2n2^n, is at least NN.

The relationship is given by the inequality:

2n≥N2^n \ge N

Given N=258N = 258:

2n≥2582^n \ge 258

Let's evaluate for different values of nn:

  • For n=8n = 8: 28=256<2582^8 = 256 < 258 (insufficient to represent 258258 states)
  • For n=9n = 9: 29=512≥2582^9 = 512 \ge 258 (sufficient)

Thus, the minimum number of D\text{D} flip-flops required is 9.

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