GATE EC Analog Circuits questions

Negative feedback in amplifiers

$\alpha$ - cut off frequency of a bipolar junction transistor

The $6 \mathrm{~V}$ Zener diode shown in given figure has zero Zener resistance and a knee current of $5 \mathrm{~mA}$. The minimum value of $R$ so that the voltage across it does not fall below $6 \mathrm{~V}$ is

The circuit of given figure, uses an ideal op amp. For small positive values of $V_{\text{in' }}$, the circuit works as

An op. amp. has an offset voltage of $1 \mathrm{mV}$ and is ideal in all other respects. If this op. amp. is used in the circuit shown in the given figure, the output voltage will be (select the nearest value)

The $\text{JFET}$ in the circuit shown in the given figure has an $\mathrm{I}_{\mathrm{DSS}}=10 \mathrm{~mA}$ and $\mathrm{V}_{\mathrm{p}}=5 \mathrm{~V}$. The value of the resistance $\mathrm{R}_{\mathrm{s}}$ for a drain current $\mathrm{I}_{\mathrm{DS}}=6.4 \mathrm{~mA}$ is (select the nearest value)

An $n$-channel $\text{JFET}$ has a pinch-off voltage of $\mathrm{V}_{p}=-5 \mathrm{~V}, \mathrm{~V}_{\mathrm{DS}}(\max )=20 \mathrm{~V}$, and $\delta_{m}=2 \mathrm{~mA} / \mathrm{V}$. The minimum ' $\mathrm{ON}^{\prime}$ ' resistance is achieved in the $\text{JEFT}$ for

A $\text{P-N}$ junction series with a $100$ ohms resistor, is forward based so that a current of $100 \mathrm{~mA}$ flows. If the voltage across this combination is instantaneously reversed to $10 \mathrm{~V}$ at $t=0$, the reverse current that flows through the diode at $t=0$ is approximately given by