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Official PYQ · 2015

GATE CS 2015 Set 3 Q41 — Sets, Relations and Functions

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Let RR be a relation on the set of ordered pairs of positive integers such that ((p,q),(r,s))∈R((p,q),(r,s)) \in R if and only if p−s=q−rp-s=q-r. Which one of the following is true about RR?

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Answer: C

Let the relation RR be defined on the set of ordered pairs of positive integers Z+×Z+\mathbb{Z}^+ \times \mathbb{Z}^+ by:

((p,q),(r,s))∈R  ⟺  p−s=q−r((p,q), (r,s)) \in R \iff p - s = q - r

Let's analyze the properties of reflexivity and symmetry for RR:

1. Reflexivity

For RR to be reflexive, every pair ((p,q),(p,q))((p,q), (p,q)) must belong to RR for all p,q∈Z+p, q \in \mathbb{Z}^+.

Applying the definition of the relation:

((p,q),(p,q))∈R  ⟺  p−q=q−p((p,q), (p,q)) \in R \iff p - q = q - p   ⟹  2p=2q  ⟹  p=q\implies 2p = 2q \implies p = q

This condition only holds when p=qp = q. For any pair where p≠qp \neq q (for example, (1,2)(1, 2)):

1−2=−1and2−1=11 - 2 = -1 \quad \text{and} \quad 2 - 1 = 1

Since −1≠1-1 \neq 1, the pair ((1,2),(1,2))∉R((1,2), (1,2)) \notin R. Therefore, RR is not reflexive.

2. Symmetry

For RR to be symmetric, if ((p,q),(r,s))∈R((p,q), (r,s)) \in R, then ((r,s),(p,q))∈R((r,s), (p,q)) \in R must also hold.

Assume ((p,q),(r,s))∈R((p,q), (r,s)) \in R:

p−s=q−rp - s = q - r

Multiplying both sides of the equation by −1-1:

−(p−s)=−(q−r)-(p - s) = -(q - r)   ⟹  s−p=r−q\implies s - p = r - q   ⟹  r−q=s−p\implies r - q = s - p

This is precisely the condition for ((r,s),(p,q))∈R((r,s), (p,q)) \in R. Therefore, RR is symmetric.

Thus, the relation RR is not reflexive but symmetric.

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