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Official PYQ · 2024

GATE CS 2024 Set 1 Q22 — Sets, Relations and Functions

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Let AA and BB be non-empty finite sets such that there exist one-to-one and onto functions (i)\text{(i)} from AA to BB and (ii)\text{(ii)} from A×AA \times A to A∪BA \cup B. The number of possible values of |A|\text{|A|} is ___________.
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Answer: 2

Let AA and BB be non-empty finite sets with ∣A∣=a|A| = a and ∣B∣=b|B| = b, where a,b≥1a, b \ge 1.

Step 1: Analyze condition (i)
There exists a bijection (one-to-one and onto function) from AA to BB. This implies: ∣A∣=∣B∣  ⟹  a=b|A| = |B| \implies a = b

Step 2: Analyze condition (ii)
There exists a bijection from A×AA \times A to A∪BA \cup B. This implies: ∣A×A∣=∣A∪B∣|A \times A| = |A \cup B| a2=∣A∣+∣B∣−∣A∩B∣a^2 = |A| + |B| - |A \cap B| a2=2a−∣A∩B∣a^2 = 2a - |A \cap B| ∣A∩B∣=2a−a2|A \cap B| = 2a - a^2

Step 3: Find the possible values of aa
Since A∩BA \cap B is a subset of AA, its size must satisfy 0≤∣A∩B∣≤a0 \le |A \cap B| \le a. Specifically, ∣A∩B∣≥0|A \cap B| \ge 0: 2a−a2≥0  ⟹  a(2−a)≥02a - a^2 \ge 0 \implies a(2 - a) \ge 0

Since AA is non-empty, a≥1a \ge 1. The only positive integers satisfying this inequality are:

  • a=1a = 1: Here, ∣A∩B∣=2(1)−12=1|A \cap B| = 2(1) - 1^2 = 1, which is valid (occurs when A=BA = B).
  • a=2a = 2: Here, ∣A∩B∣=2(2)−22=0|A \cap B| = 2(2) - 2^2 = 0, which is valid (occurs when A∩B=∅A \cap B = \emptyset).

Thus, the possible values for ∣A∣|A| are 11 and 22. The number of possible values is 22.

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