Skip to content
Official PYQ · 2002

GATE CS 2002 Q2.17 — Sets, Relations and Functions

Explain with AI

The binary relation S=ϕ(empty set)S= \phi \text{(empty set)} on a set A={1,2,3}A = \left \{ 1,2,3 \right \} is 

Choose one option
View worked solution

Answer: D

To determine the properties of the empty relation S=∅S = \emptyset on the set A={1,2,3}A = \{1, 2, 3\}, we test the standard definitions of binary relations:

  1. Reflexivity: A relation RR on AA is reflexive if for every a∈Aa \in A, (a,a)∈R(a, a) \in R.
    For S=∅S = \emptyset, the elements (1,1),(2,2),(3,3)(1,1), (2,2), (3,3) are not in SS. Thus, SS is not reflexive.
  2. Symmetry: A relation RR on AA is symmetric if for all a,b∈Aa, b \in A, (a,b)∈R  ⟹  (b,a)∈R(a, b) \in R \implies (b, a) \in R.
    Since S=∅S = \emptyset, the premise (a,b)∈S(a, b) \in S is always false. Therefore, the implication holds vacuously. Thus, SS is symmetric.
  3. Transitivity: A relation RR on AA is transitive if for all a,b,c∈Aa, b, c \in A, ((a,b)∈R and (b,c)∈R)  ⟹  (a,c)∈R((a, b) \in R \text{ and } (b, c) \in R) \implies (a, c) \in R.
    Since S=∅S = \emptyset, the premise ((a,b)∈S and (b,c)∈S)((a, b) \in S \text{ and } (b, c) \in S) is always false. Therefore, this implication also holds vacuously. Thus, SS is transitive.

Since the relation SS is both transitive and symmetric (but not reflexive), the correct option is D.

Free practice · Your answers on this page are not saved.

Published
Report a correction
Keep exploringMore Sets, Relations and Functions questions