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Official PYQ · 2015

GATE CS 2015 Set 2 Q18 — Sets, Relations and Functions

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The cardinality of the power set of {0,1,2,…,10}\{0, 1, 2, \dots , 10\} is _______
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Answer: 2048

Let the given set be S={0,1,2,…,10}S = \{0, 1, 2, \dots, 10\}.

First, we determine the cardinality (the number of elements) of the set SS:

  • The elements are integers starting from 00 up to 1010.
  • The number of elements, ∣S∣=10−0+1=11|S| = 10 - 0 + 1 = 11.

The power set of SS, denoted by P(S)\mathcal{P}(S), is the set of all subsets of SS. If a set has nn elements, the cardinality of its power set is given by the formula:

∣P(S)∣=2n\lvert\mathcal{P}(S)\rvert = 2^n

Substituting n=11n = 11 into the formula:

∣P(S)∣=211=2048\lvert\mathcal{P}(S)\rvert = 2^{11} = 2048

Thus, the cardinality of the power set is 2048.

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