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Official PYQ · 2013

GATE CS 2013 Q1 — Sets, Relations and Functions

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A binary operation ⊕\oplus on a set of integers is defined as x⊕y=x2+y2x \oplus y = x^{2}+y^{2}. Which one of the following statements is TRUE about ⊕\oplus?

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Answer: A

To determine the properties of the binary operation x⊕y=x2+y2x \oplus y = x^2 + y^2 on the set of integers, we check for commutativity and associativity:

  • Commutativity: An operation ⊕\oplus is commutative if x⊕y=y⊕xx \oplus y = y \oplus x for all integers xx and yy.
    x⊕y=x2+y2x \oplus y = x^2 + y^2y⊕x=y2+x2=x2+y2y \oplus x = y^2 + x^2 = x^2 + y^2Since addition of integers is commutative, x⊕y=y⊕xx \oplus y = y \oplus x. Thus, the operation is commutative.
  • Associativity: An operation ⊕\oplus is associative if (x⊕y)⊕z=x⊕(y⊕z)(x \oplus y) \oplus z = x \oplus (y \oplus z) for all integers x,y,x, y, and zz.
    Let us test this with a simple counterexample using x=1,y=2,x = 1, y = 2, and z=3z = 3:
    (1⊕2)⊕3=(12+22)⊕3=5⊕3=52+32=25+9=34(1 \oplus 2) \oplus 3 = (1^2 + 2^2) \oplus 3 = 5 \oplus 3 = 5^2 + 3^2 = 25 + 9 = 341⊕(2⊕3)=1⊕(22+32)=1⊕13=12+132=1+169=1701 \oplus (2 \oplus 3) = 1 \oplus (2^2 + 3^2) = 1 \oplus 13 = 1^2 + 13^2 = 1 + 169 = 170Since 34≠17034 \neq 170, the operation is not associative.

Hence, the operation is commutative but not associative.

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