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Official PYQ · 2024

GATE CS 2024 Set 2 Q9 — General Aptitude

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​​​​A cube is to be cut into 88 pieces of equal size and shape. Here, each cut should be straight and it should not stop till it reaches the other end of the cube.

The minimum number of such cuts required is

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Answer: A

To divide a cube into 88 pieces of equal size and shape using straight, end-to-end cuts, we can make cuts along its three mutually perpendicular axes (length, width, and height).

Let xx, yy, and zz be the number of cuts made along the three dimensions. The total number of pieces NN obtained is given by the formula:

N=(x+1)(y+1)(z+1)N = (x + 1)(y + 1)(z + 1)

We are given that N=8N = 8. To minimize the total number of cuts, T=x+y+zT = x + y + z, we should distribute the factors of 88 as evenly as possible among the three dimensions:

8=2×2×28 = 2 \times 2 \times 2

Comparing the terms:

  • x+1=2  ⟹  x=1x + 1 = 2 \implies x = 1
  • y+1=2  ⟹  y=1y + 1 = 2 \implies y = 1
  • z+1=2  ⟹  z=1z + 1 = 2 \implies z = 1

Thus, the minimum number of cuts required is:

T=x+y+z=1+1+1=3T = x + y + z = 1 + 1 + 1 = 3

These 33 mutually perpendicular cuts (one horizontal and two vertical) divide the cube into 88 identical smaller cubes.

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