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Official PYQ · 2024

GATE CS 2024 Set 1 Q9 — General Aptitude

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A rectangular paper of 20 cm×8 cm20 \mathrm{~cm} \times 8 \mathrm{~cm} is folded 33 times. Each fold is made along the line of symmetry, which is perpendicular to its long edge. The perimeter of the final folded sheet (in cm\mathrm{cm} ) is

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Answer: A

Let us track the dimensions of the rectangular sheet after each fold. Initially, the dimensions are 20 cm×8 cm20\text{ cm} \times 8\text{ cm}.

  1. Initial State:
    • Dimensions: 20 cm×8 cm20\text{ cm} \times 8\text{ cm}
    • The long edge is 20 cm20\text{ cm}.
  2. First Fold:
    • The fold is made perpendicular to the long edge (20 cm20\text{ cm}), halving it.
    • New dimensions: 202 cm×8 cm=10 cm×8 cm\frac{20}{2}\text{ cm} \times 8\text{ cm} = 10\text{ cm} \times 8\text{ cm}
    • The long edge is now 10 cm10\text{ cm}.
  3. Second Fold:
    • The fold is made perpendicular to the current long edge (10 cm10\text{ cm}), halving it.
    • New dimensions: 102 cm×8 cm=5 cm×8 cm\frac{10}{2}\text{ cm} \times 8\text{ cm} = 5\text{ cm} \times 8\text{ cm}
    • The long edge is now 8 cm8\text{ cm}.
  4. Third Fold:
    • The fold is made perpendicular to the current long edge (8 cm8\text{ cm}), halving it.
    • New dimensions: 5 cm×82 cm=5 cm×4 cm5\text{ cm} \times \frac{8}{2}\text{ cm} = 5\text{ cm} \times 4\text{ cm}

The final folded sheet has dimensions 5 cm×4 cm5\text{ cm} \times 4\text{ cm}.

The perimeter of this final sheet is calculated as: Perimeter=2×(length+width)=2×(5+4)=18 cm\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (5 + 4) = 18\text{ cm}

Thus, the correct option is A.

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