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Official PYQ · 2021

GATE CS 2021 Set 2 Q37 — Sets, Relations and Functions

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For two nn-dimensional real vectors PP and QQ, the operation s(P,Q)s(P,Q) is defined as follows:

s(P,Q)=∑i=1n(P[i]⋅Q[i])s(P,Q) = \displaystyle \sum_{i=1}^n (P[i] \cdot Q[i])

Let L\mathcal{L} be a set of 1010-dimensional non-zero real vectors such that for every pair of distinct vectors P,Q∈LP,Q \in \mathcal{L}, s(P,Q)=0s(P,Q)=0. What is the maximum cardinality possible for the set L\mathcal{L}?

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Answer: B

The given operation s(P,Q)=∑i=1n(P[i]⋅Q[i])s(P, Q) = \sum_{i=1}^n (P[i] \cdot Q[i]) represents the standard inner product (dot product) of two vectors PP and QQ in Rn\mathbb{R}^n. Here, n=10n = 10.

We are given that:

  • L\mathcal{L} is a set of 1010-dimensional non-zero real vectors.
  • For every pair of distinct vectors P,Q∈LP, Q \in \mathcal{L}, s(P,Q)=0s(P, Q) = 0. This means the vectors in L\mathcal{L} are pairwise orthogonal.

A fundamental theorem in linear algebra states that any set of pairwise orthogonal non-zero vectors is linearly independent.

Since the vectors belong to a 1010-dimensional vector space R10\mathbb{R}^{10}, the maximum number of linearly independent vectors possible in this space is equal to its dimension, which is 1010.

Thus, the maximum cardinality of the set L\mathcal{L} is 1010.

Therefore, the correct option is B.

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