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Official PYQ · 1995

GATE CS 1995 Q1.20 — Sets, Relations and Functions

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The number of elements in the power set P(S)P(S) of the set S={{∅},1,{2,3}}S=\{\{\emptyset\}, 1, \{2, 3\}\} is:

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Answer: C

To find the number of elements in the power set P(S)P(S) of the set SS, we first need to determine the cardinality (the number of elements) of SS.

The given set is:

S={{∅},1,{2,3}}S = \{\{\emptyset\}, 1, \{2, 3\}\}

Let us list the distinct elements of SS:

  1. The first element is the set containing the empty set: {∅}\{\emptyset\}
  2. The second element is the number: 11
  3. The third element is the set: {2,3}\{2, 3\}

Since all three elements are distinct, the cardinality of SS is:

∣S∣=3|S| = 3

The power set P(S)P(S) is the set of all subsets of SS. The number of elements in the power set of any finite set SS is given by 2∣S∣2^{|S|}.

∣P(S)∣=23=8|P(S)| = 2^3 = 8

Therefore, the number of elements in the power set P(S)P(S) is 88.

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