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Official PYQ · 1993Q6.4Concept of Layering: OSI and TCP/IP Protocol StacksMCQ1 mark

GATE CS 1993 Q6.4 — Concept of Layering: OSI and TCP/IP Protocol Stacks

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Assume that each character code consists of 88 bits. The number of characters that can be transmitted per second through an asynchronous serial line at 24002400 baud rate, and with two stop bits is

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Answer: C

In asynchronous serial communication, each character is transmitted inside a frame that includes overhead bits for synchronization. A standard frame consists of:

  • Start bit: 11 bit (always required in asynchronous transmission to signal the start of a character)
  • Data bits: 88 bits (given)
  • Stop bits: 22 bits (given)

Therefore, the total number of bits required to transmit one character is:

Total bits per character=1 (start)+8 (data)+2 (stop)=11 bits\text{Total bits per character} = 1 \text{ (start)} + 8 \text{ (data)} + 2 \text{ (stop)} = 11 \text{ bits}

The baud rate is given as 24002400 baud. Assuming binary signaling (where 1 baud=1 bit per second1 \text{ baud} = 1 \text{ bit per second}), the transmission speed is 2400 bits per second (bps)2400 \text{ bits per second (bps)}.

The number of characters transmitted per second is:

Characters per second=Baud rateTotal bits per character=240011≈218.18\text{Characters per second} = \frac{\text{Baud rate}}{\text{Total bits per character}} = \frac{2400}{11} \approx 218.18

Thus, 218218 complete characters can be transmitted per second, which matches Option C.

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