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Official PYQ · 2010

GATE CS 2010 Q3 — Sets, Relations and Functions

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What is the possible number of reflexive relations on a set of 55 elements?

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Answer: C

A relation RR on a set AA with nn elements is a subset of the Cartesian product A×AA \times A. The total number of ordered pairs in A×AA \times A is n2n^2.

For a relation RR to be reflexive, it must contain all diagonal elements of the form (a,a)(a, a) for every a∈Aa \in A.

  • Diagonal elements: There are exactly nn such elements, and all of them must be included in the relation (only 11 choice for each).
  • Non-diagonal elements: There are n2−nn^2 - n remaining elements. Each of these elements can either be included or excluded from the relation (exactly 22 choices for each).

Therefore, the total number of reflexive relations on a set of nn elements is given by:

Number of reflexive relations=2n2−n=2n(n−1)\text{Number of reflexive relations} = 2^{n^2 - n} = 2^{n(n-1)}

Given n=5n = 5:

Number of reflexive relations=25(5−1)=25×4=220\text{Number of reflexive relations} = 2^{5(5-1)} = 2^{5 \times 4} = 2^{20}

Hence, the correct option is C.

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