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Official PYQ · 2004Q22Concept of Layering: OSI and TCP/IP Protocol StacksMCQ1 mark

GATE CS 2004 Q22 — Concept of Layering: OSI and TCP/IP Protocol Stacks

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How many 8−bi8-bit characters can be transmitted per second over a 96009600 baud serial communication link using asynchronous mode of transmission with one start bit, eight data bits, two stop bits and one parity bit?

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Answer: B

To find the number of characters transmitted per second, we first determine the total number of bits required to transmit a single 88-bit character (including the overhead bits).

For each character, the transmission frame consists of:

  • Start bit: 11 bit
  • Data bits: 88 bits
  • Parity bit: 11 bit
  • Stop bits: 22 bits

Total bits per character=1+8+1+2=12 bits\text{Total bits per character} = 1 + 8 + 1 + 2 = 12 \text{ bits}

The baud rate of the serial link is 96009600 baud. In standard binary serial communication, 11 baud corresponds to 11 bit per second (bps). Therefore, the transmission speed is 9600 bps9600 \text{ bps}.

The number of characters transmitted per second is calculated as:

Characters per second=Baud rateTotal bits per character=960012=800\text{Characters per second} = \frac{\text{Baud rate}}{\text{Total bits per character}} = \frac{9600}{12} = 800

Thus, 800800 characters can be transmitted per second.

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