GATE EC Op-amp Circuits questions

In the given circuit, $V_{0}$ is

In given figure, the steady state output voltage corresponding to the input voltage $3+4 \sin 100 t \mathrm{~V}$ is

if the $\text{op-amp}$ in given figure, has an input offset voltage of $5 \; \mathrm{mV}$ and an open-loop voltage gain of $10,000,$ then $v_{0}$ will be

For the circuit in the figure, the voltage $v_{0}$ is

Negative feedback in an amplifier

The first dominant pole encountered in the frequency response of a compensated $\text{op - amp}$ is approximately at

An amplifier has an open-loop gain of $100$, an input impedance of $1 \; \mathrm{k \Omega}$, and an output impedance of $100 \; \Omega$. A feedback network with a feedback factor of $0.99$ is connected to the amplifier in a voltage series feedback mode. The new input and output impedances, respectively, are

One input terminal of high gain comparator circuit is connected to ground and a sinusoidal voltage is applied to the other input. The output of comparator will be

The circuit of the figure is an example of feedback of the following type

The voltage $\mathrm{V}$ in the figure is always equal to

The voltage $\mathrm{V}$ in the figure is equal to

The output voltage $V_{0}$ of the circuit shown in the figure is

In the circuit shown in the given figure $\mathrm{N}$ is a finite gain amplifier with a gain of $k$, a very large input impedance, and a very low output impedance. The input impedance of the feedback amplifier with the feedback impedance $\mathrm{Z}$ connected as shown will be

The circuit shown in the figure is that of

Value of $R$ in the oscillator circuit shown in the given figure, so chosen that it just oscillates at an angular frequency of $\omega$. The value of $\omega$ and the required value of $R$ will respectively be

To obtain very high input and output impedances in a feedback amplifier, the topolomostly used is

Negative feedback in amplifiers

The circuit of given figure, uses an ideal op amp. For small positive values of $V_{\text{in' }}$, the circuit works as

An op. amp. has an offset voltage of $1 \mathrm{mV}$ and is ideal in all other respects. If this op. amp. is used in the circuit shown in the given figure, the output voltage will be (select the nearest value)