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GATE EC LTI Systems questions

Practise LTI Systems questions for GATE EC. Explore official PYQs and original topic-wise quizzes, check answers and view available solutions. Free, no sign-in.

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Official PYQ2014Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
Let h(t)h(t) denote the impulse response of a causal system with transfer function 1s+1.\frac{1}{s+1}. Consider the following three statements. S1S1: The system is stable. S2S2: h(t+1)h(t)\frac{h(t+1)}{h(t)} is independent of tt for t>0t > 0. S3S3: A non-causal system with the same transfer function is stable. For the above system,
Official PYQ2014Networks, Signals and SystemsLTI SystemsNAT · 2 marks
The steady state error of the system shown in the figure for a unit step input is _________.
Official PYQ2014Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
In the root locus plot shown in the figure, the pole/zero marks and the arrows have been removed. Which one of the following transfer functions has this root locus?
Official PYQ2014Networks, Signals and SystemsLTI SystemsMCQ · 1 mark
A real-valued signal x(t)x(t) limited to the frequency band ∣f∣≤W2\mid f \mid \leq \frac{W}{2} is passed through a linear time invariant system whose frequency response is H(f)={e−j4πf,∣f∣≤W20,∣f∣>W2.H(f) = \begin{cases} e^{-j 4 \pi f}, & \mid f \mid \leq \frac{W}{2} \\ 0, & \mid f \mid > \frac{W}{2} \end{cases}. The output of the system is
Official PYQ2014Networks, Signals and SystemsLTI SystemsNAT · 1 mark
The sequence x[n]=0.5n u[n]x[n] = 0.5^n \: u[n], where u[n]u[n] is the unit step sequence, is convolved with itself to obtain y[n]y[n]. Then Σn=−∞+∞y[n]\Sigma_{n= -\infty}^{+ \infty} y[n] is _________.
Official PYQ2014Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
A stable linear time variant (LTI) system has a transfer function H(s)=1s2+s−6H(s) = \frac{1}{s^2+s-6}. To make this system casual it needs to be cascaded with another LTI system having a transfer function H1(s)H_1(s). A correct choice for H1(s)H_1(s) among the following options is
Official PYQ2014Networks, Signals and SystemsLTI SystemsNAT · 2 marks
A casual LTI system has zero initial conditions and impulse response h(t)h(t). Its input x(t)x(t) and output y(t)y(t) are related through the linear constant-coefficient differential equation d2y(t)dt2+ady(t)dt+a2y(t)=x(t).\frac{d^2y(t)}{dt^2} + a \frac{dy(t)}{dt}+a^2y(t)=x(t). Let another signal g(t)g(t) be defined as g(t)=a2∫0th(τ)dτ+dh(t)dt+ah(t).g(t)=a^2 \int_0^t h(\tau) d \tau +\frac{dh(t)}{dt}+ah(t). If …
Official PYQ2014Networks, Signals and SystemsLTI SystemsNAT · 2 marks
Consider a transfer function Gp(s)=ps2+3ps−2s2+(3+p)s+(2−p)G_p(s) = \frac{ps^2+3ps-2}{s^2+(3+p)s+(2-p)} with pp a positive real parameter. The maximum value of pp until which GpG_p remains stable is ___________.
Official PYQ2014Networks, Signals and SystemsLTI SystemsNAT · 2 marks
The characteristic equation of a unity negative feedback system is 1+KG(s)=01+KG(s)=0. The open loop transfer function G(s)G(s) has one pole at 00 and two poles at −1-1. The root locus of the system for varying KK is shown in the figure. The constant damping ratio line, for ξ=0.5\xi = 0.5, intersects the root locus at point A. The distance from the origin …
Official PYQ2013Networks, Signals and SystemsLTI SystemsMCQ · 1 mark
Two systems with impulse responses h1(t)h_{1}(t) and h2(t)h_{2}(t) are connected in cascade. Then the overall impulse response of the cascaded system is given by
Official PYQ2013Networks, Signals and SystemsLTI SystemsMCQ · 1 mark
The impulse response of a system is h(t)=tu(t).h(t) = tu(t). For an input u(t−1),u(t − 1), the output is
Official PYQ2013Networks, Signals and SystemsLTI SystemsMCQ · 1 mark
Which one of the following statements is NOT TRUE for a continuous time causal and stable LTI system?
Official PYQ2013Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
The open-loop transfer function of a dc motor is given as ω(s)Va(s)=101+10s.\dfrac{\omega(s)}{V_{a}(s)} = \dfrac{10}{1+10s}. When connected in feedback as shown below, the approximate value of KaK_{a} that will reduce the time constant of the closed loop system by one hundred times as compared to that of the open-loop system is
Official PYQ2013Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
The impulse response of a continuous time system is given by h(t)=δ(t−1)+δ(t−3).h(t) = \delta(t-1) + \delta(t-3). The value of the step response at t=2t = 2 is
Official PYQ2013Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
The state diagram of a system is shown below. A system is described by the state-variable equations X˙=AX+Bu;  y=CX+Du\dot{X}= AX+Bu;\:\: y = CX+Du The state-variable equations of the system shown in the figure above are
Official PYQ2012Networks, Signals and SystemsLTI SystemsMCQ · 1 mark
A system with transfer function G(s)=(s2+9)(s+2)(s+1)(s+3)(s+4)G(s)=\frac{(s^2+9)(s+2)}{(s+1)(s+3)(s+4)} is excited by sin⁡(ωt)\sin(\omega t). The steady-state output of the system is zero at
Official PYQ2012Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
The state variable description of an LTI system is given by (x1˙x2˙x3˙)=(0a1000a2a300)(x1x2x3)+(001)u\begin{pmatrix} \dot{x_1}\\ \dot{x_2}\\ \dot{x_3} \end{pmatrix}=\begin{pmatrix} 0 & a_1 & 0\\ 0 & 0 & a_2\\a_3 & 0 & 0 \end{pmatrix} \begin{pmatrix} x_1\\ x_2\\x_3 \end{pmatrix}+\begin{pmatrix} 0\\ 0\\1 \end{pmatrix}u …
Official PYQ2012Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
Let y[n]y[n] denote the convolution of h[n]h[n] and g[n]g[n], where h[n]=(12)nu[n]h[n]=(\frac{1}{2})^nu[n] and g[n]g[n] is a casual sequence. If y[0]=1y[0]=1 and y[1]=12y[1]=\frac{1}{2}, then g[1]g[1] equals
Official PYQ2012Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
The transfer function of a compensator is given as Gc(s)=s+as+bG_c(s)=\frac{s+a}{s+b} Gc(s)G_c(s) is a lead compensator if
Official PYQ2012Networks, Signals and SystemsLTI SystemsMCQ · 2 marks
The transfer function of a compensator is given as Gc(s)=s+as+bG_c(s)=\frac{s+a}{s+b} The phase of the above lead compensator is maximum at