GATE EC 2005 Set 1 Q54 — Combinatorial Circuits

The Boolean expression for the truth table shown is
$$\begin{array}{|c|c|c|c|} \hline \mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{F} \\ \hline 0 & 0 & 0 & 0 \\ \hline 0 & 0 & 1 & 0 \\ \hline 0 & 1 & 0 & 0 \\ \hline 0 & 1 & 1 & 1 \\ \hline 1 & 0 & 0 & 0 \\ \hline 1 & 0 & 1 & 0 \\ \hline 1 & 1 & 0 & 1 \\ \hline 1 & 1 & 1 & 0 \\ \hline \end{array}$$