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GATE CS 1987 Q1-xxi — Linear Algebra: Matrices, Determinants, System of Linear Equations

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If a,b,a, b, and cc are constants, which of the following is a linear inequality?

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Answer: C

A linear inequality in two variables xx and yy is an inequality that can be written in one of the following forms:

Ax+By<C,Ax+By≤C,Ax+By>C,orAx+By≥CAx + By < C, \quad Ax + By \le C, \quad Ax + By > C, \quad \text{or} \quad Ax + By \ge C

where A,B,A, B, and CC are constants, and the variables xx and yy are of first degree (exponent of 11) with no product terms like xyxy.

Let's evaluate each option given that a,b,a, b, and cc are constants:

  • Option A: ax+bcy=0ax + bcy = 0
    This is a linear equation, not an inequality.
  • Option B: ax2+cy2=21ax^2 + cy^2 = 21
    This is a non-linear equation due to the x2x^2 and y2y^2 terms.
  • Option C: abx+a2y≥15abx + a^2y \ge 15
    Since aa and bb are constants, the coefficients abab and a2a^2 are also constants. This inequality is of the form Ax+By≥CAx + By \ge C, which is a linear inequality.
  • Option D: xy+ax≥20xy + ax \ge 20
    This is non-linear because of the product term xyxy (which has a degree of 2).

Therefore, the correct option is C.

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