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Official PYQ · 2015

GATE CS 2015 Set 1 QGA-9 — General Aptitude

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The pie chart below has the breakup of the number of students from different departments in an engineering college for the year 20122012. The proportion of male to female students in each department is 5:45:4. There are 4040 males in Electrical Engineering. What is the difference between the numbers of female students in the civil department and the female students in the Mechanical department?

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Answer: 32

From the given pie chart, the distribution of students in different departments is:

  • Electrical Engineering (EE): 20%20\%
  • Civil Engineering (CE): 30%30\%
  • Mechanical Engineering (ME): 10%10\%

The ratio of male to female students in each department is 5:45:4. We are given that there are 4040 male students in Electrical Engineering.

First, let us find the total number of students in the Electrical Engineering department:

Females in EE=40×45=32\text{Females in EE} = 40 \times \frac{4}{5} = 32Total students in EE=40+32=72\text{Total students in EE} = 40 + 32 = 72

Since EE represents 20%20\% of the total students, we have:

20% of Total Students=7220\% \text{ of Total Students} = 72

We need to find the difference between the number of female students in Civil (30%30\%) and Mechanical (10%10\%) departments:

Difference in total students (CE - ME)=30%−10%=20%\text{Difference in total students (CE - ME)} = 30\% - 10\% = 20\%

Since 20%20\% of the total students is 7272, the difference in total students between CE and ME is exactly 7272. Since the proportion of females in any department is 49\frac{4}{9}, the difference in female students is:

Difference in females=49×72=32\text{Difference in females} = \frac{4}{9} \times 72 = 32

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