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Official PYQ · 2015

GATE CS 2015 Set 1 QGA-6 — General Aptitude

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The number of students in a class who have answered correctly, wrongly, or not attempted each question in an exam, are listed in the table below. The marks for each question are also listed. There is no negative or partial marking.Q No.MarksAnsweredAnsweredNot CorrectlyWronglyAttempted12211762315272311129442231835531121\begin{array}{|c|c|c|c|c|} \hline \textbf{Q No.} & \textbf{Marks} &\textbf{Answered}&\textbf{Answered}&\textbf{Not}\\&&\textbf{ Correctly} &\textbf{Wrongly} & \textbf{Attempted} \\ \hline \text{1} & \text{2} &\text{21} &\text{17} &\text{6}\\ \hline \text{2} & \text{3} &\text{15} & \text{27}& \text{2}\\ \hline \text{3} & \text{1} &\text{11} & \text{29} & \text{4}\\ \hline \text{4} & \text{2} &\text{23} & \text{18} & \text{3}\\ \hline \text{5} & \text{5} &\text{31} & \text{12} & \text{1} \\ \hline \end{array}What is the average of the marks obtained by the class in the examination?

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Answer: C

To find the average marks obtained by the class, we first need to determine the total number of students in the class and the total marks obtained by all students combined.

Step 1: Determine the total number of students (NN)

The total number of students in the class can be found by summing the students who answered correctly, wrongly, or did not attempt any single question. Let's verify this using Question 1:

Total students (N)=21 (Correct)+17 (Wrong)+6 (Not Attempted)=44\text{Total students } (N) = 21 \text{ (Correct)} + 17 \text{ (Wrong)} + 6 \text{ (Not Attempted)} = 44

Checking other questions confirms that the class size is consistently N=44N = 44.

Step 2: Calculate the total marks obtained by the class

Since there is no negative or partial marking, marks are only awarded for correct answers.

Total Marks=∑(Marks per Question×Number of Correct Answers)=(2×21)+(3×15)+(1×11)+(2×23)+(5×31)=42+45+11+46+155=299\begin{align*} \text{Total Marks} &= \sum (\text{Marks per Question} \times \text{Number of Correct Answers}) \\ &= (2 \times 21) + (3 \times 15) + (1 \times 11) + (2 \times 23) + (5 \times 31) \\ &= 42 + 45 + 11 + 46 + 155 \\ &= 299 \end{align*}

Step 3: Calculate the average marks

Average Marks=Total MarksTotal Students=29944≈6.795\text{Average Marks} = \frac{\text{Total Marks}}{\text{Total Students}} = \frac{299}{44} \approx 6.795

Thus, the average of the marks obtained by the class is 6.795, which corresponds to Option C.

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