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GATE CS 2001 Q1.1 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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Consider the following statements:

  • S1: The sum of two singular n×nn \times n matrices may be non-singular
  • S2: The sum of two n×nn \times n non-singular matrices may be singular


Which one of the following statements is correct?

Choose one option
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Answer: A

We can determine the truth value of both statements by constructing simple examples using 2×22 \times 2 matrices (n=2n = 2).

Statement S1: The sum of two singular n×nn \times n matrices may be non-singular.

Let us consider two singular matrices AA and BB:

A=(1000)andB=(0001)A = \begin{pmatrix} 1 & 0 \\ 0 & 0 \end{pmatrix} \quad \text{and} \quad B = \begin{pmatrix} 0 & 0 \\ 0 & 1 \end{pmatrix}

Both AA and BB are singular because det⁡(A)=0\det(A) = 0 and det⁡(B)=0\det(B) = 0.

Their sum is:

A+B=(1001)=IA + B = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} = I

Since det⁡(I)=1≠0\det(I) = 1 \neq 0, the sum A+BA + B is non-singular. Thus, S1 is true.

Statement S2: The sum of two n×nn \times n non-singular matrices may be singular.

Let us consider two non-singular matrices CC and DD:

C=(1001)=IandD=(−100−1)=−IC = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} = I \quad \text{and} \quad D = \begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix} = -I

Both CC and DD are non-singular because det⁡(C)=1≠0\det(C) = 1 \neq 0 and det⁡(D)=1≠0\det(D) = 1 \neq 0.

Their sum is:

C+D=(0000)=OC + D = \begin{pmatrix} 0 & 0 \\ 0 & 0 \end{pmatrix} = O

Since det⁡(O)=0\det(O) = 0, the sum C+DC + D is singular. Thus, S2 is true.

Since both S1S1 and S2S2 are true, the correct option is A.

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