Answer: A
To find the correct relation, we can test the options by substituting the values for i>0 from the given table.
Step 1: Verify the relation for X(i)
Let us test the relation X(i)=X(i−1)+I(i) for i=1,2,3:
- For i=1:
X(1)=X(0)+I(1)=20+(−4)=16
This matches the table value X(1)=16.
- For i=2:
X(2)=X(1)+I(2)=16+10=26
This matches the table value X(2)=26.
- For i=3:
X(3)=X(2)+I(3)=26+15=41
This matches the table value X(3)=41.
Thus, the relation X(i)=X(i−1)+I(i) is correct.
Step 2: Verify the relation for Y(i)
Let us test the relation Y(i)=Y(i−1)×I(i) for i=1,2,3:
- For i=1:
Y(1)=Y(0)×I(1)=20×(−4)=−80
This matches the table value Y(1)=−80.
- For i=2:
Y(2)=Y(1)×I(2)=−80×10=−800
This matches the table value Y(2)=−800.
- For i=3:
Y(3)=Y(2)×I(3)=−800×15=−12000
This matches the table value Y(3)=−12000.
Thus, the relation Y(i)=Y(i−1)×I(i) is also correct.
Conclusion
Both relations in Option A match the given data perfectly.