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Official PYQ · 2024

GATE CS 2024 Set 2 Q7 — General Aptitude

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​​​​​​A person sold two different items at the same price. He made 10%10 \% profit in one item, and 10%10 \% loss in the other item. In selling these two items, the person made a total of

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Answer: C

We can solve this problem using two methods: a standard shortcut formula and a detailed step-by-step derivation.

Method 1: Using the Standard Formula

When two items are sold at the same selling price (SPSP), one at a profit of x%x\% and the other at a loss of x%x\%, there is always a net loss. The net loss percentage is given by:

Net Loss %=(x10)2%\text{Net Loss \%} = \left(\frac{x}{10}\right)^2 \%

Given x=10x = 10:

Net Loss %=(1010)2%=12%=1% loss\text{Net Loss \%} = \left(\frac{10}{10}\right)^2 \% = 1^2 \% = 1\% \text{ loss}

Method 2: Step-by-Step Derivation

Let the selling price (SPSP) of each item be 100100.

  • For the first item (10% profit):
    CP1×1.10=100  ⟹  CP1=1001.1=100011≈90.91CP_1 \times 1.10 = 100 \implies CP_1 = \frac{100}{1.1} = \frac{1000}{11} \approx 90.91
  • For the second item (10% loss):
    CP2×0.90=100  ⟹  CP2=1000.9=10009≈111.11CP_2 \times 0.90 = 100 \implies CP_2 = \frac{100}{0.9} = \frac{1000}{9} \approx 111.11

Now, calculate the total cost price (CPCP) and total selling price (SPSP):

  • Total SP=100+100=200SP = 100 + 100 = 200
  • Total CP=100011+10009=1000(9+1199)=2000099≈202.02CP = \frac{1000}{11} + \frac{1000}{9} = 1000 \left( \frac{9 + 11}{99} \right) = \frac{20000}{99} \approx 202.02

Since total CP>CP > total SPSP, there is a net loss:

Loss %=(Total CP−Total SPTotal CP)×100\text{Loss \%} = \left( \frac{\text{Total } CP - \text{Total } SP}{\text{Total } CP} \right) \times 100Loss %=(2000099−2002000099)×100=(20000−1980020000)×100=20020000×100=1%\text{Loss \%} = \left( \frac{\frac{20000}{99} - 200}{\frac{20000}{99}} \right) \times 100 = \left( \frac{20000 - 19800}{20000} \right) \times 100 = \frac{200}{20000} \times 100 = 1\%

Thus, the person made a total of 1% loss.

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