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Official PYQ · 2024

GATE CS 2024 Set 1 Q8 — General Aptitude

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The pie chart presents the percentage contribution of different macronutrients to a typical 2,000  kcal2,000\; \mathrm{kcal} diet of a person.

The typical energy density (kcal/g)(\mathrm{kcal} / \mathrm{g}) of these macronutrients is given in the table.

MacronutrientEnergy density (kcal/g)Carbohydrates4Proteins4Unsaturated fat9Saturated fat9Trans fat9\begin{array}{|c|c|} \hline \text{Macronutrient} & \text{Energy density (kcal/g)} \\ \hline \text{Carbohydrates} & \text{4} \\ \hline \text{Proteins} & \text{4} \\ \hline \text{Unsaturated fat} & \text{9} \\ \hline \text{Saturated fat} & \text{9} \\ \hline \text{Trans fat} & \text{9} \\ \hline \end{array}

The total fat (all three types), in grams, this person consumes is 

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Answer: C

From the pie chart, the percentage contributions of the three types of fats to the total daily energy intake are:

  • Saturated fat: 15%15\%
  • Unsaturated fat: 25%25\%
  • Trans fat: 5%5\%

The total percentage contribution of all fats combined is:

Total Fat Percentage=15%+25%+5%=45%\text{Total Fat Percentage} = 15\% + 25\% + 5\% = 45\%

Given that the total daily diet is 2,000 kcal2,000\text{ kcal}, the energy obtained from total fat is:

Energy from Fat=45% of 2,000 kcal=0.45×2,000=900 kcal\text{Energy from Fat} = 45\% \text{ of } 2,000\text{ kcal} = 0.45 \times 2,000 = 900\text{ kcal}

From the given table, the energy density of all three types of fat is 9 kcal/g9\text{ kcal/g}. Therefore, the total mass of fat consumed is:

Total Fat (g)=Energy from FatEnergy Density of Fat=900 kcal9 kcal/g=100 g\text{Total Fat (g)} = \frac{\text{Energy from Fat}}{\text{Energy Density of Fat}} = \frac{900\text{ kcal}}{9\text{ kcal/g}} = 100\text{ g}

Thus, the correct option is C.

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