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Official PYQ · 2016

GATE CS 2016 Set 2 Q06 — Eigenvalues and Eigenvectors, LU Decomposition

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Suppose that the eigenvalues of matrix AA are 1,2,41, 2, 4. The determinant of (A−1)T\left(A^{-1}\right)^{T} is _________.
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Answer: 0.125

We are given that the eigenvalues of the matrix AA are λ1=1\lambda_1 = 1, λ2=2\lambda_2 = 2, and λ3=4\lambda_3 = 4.

Using the properties of determinants and eigenvalues:

  1. Determinant of AA: The determinant of a matrix is equal to the product of its eigenvalues. det⁡(A)=λ1×λ2×λ3=1×2×4=8\det(A) = \lambda_1 \times \lambda_2 \times \lambda_3 = 1 \times 2 \times 4 = 8
  2. Determinant of Transpose: The determinant of the transpose of a matrix is equal to the determinant of the matrix itself. det⁡((A−1)T)=det⁡(A−1)\det\left(\left(A^{-1}\right)^T\right) = \det(A^{-1})
  3. Determinant of Inverse: The determinant of the inverse of a matrix is the reciprocal of its determinant. det⁡(A−1)=1det⁡(A)\det(A^{-1}) = \frac{1}{\det(A)}

Combining these properties, we get:

det⁡((A−1)T)=1det⁡(A)=18=0.125\det\left(\left(A^{-1}\right)^T\right) = \frac{1}{\det(A)} = \frac{1}{8} = 0.125

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