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Official PYQ · 2026

GATE CS 2026 Set 1 Q3 — Eigenvalues and Eigenvectors, LU Decomposition

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For n>1n>1, the maximum multiplicity of any eigenvalue of an n×nn \times n matrix with elements from R\mathbb{R} is

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Answer: A

The characteristic equation of an n×nn \times n matrix AA is given by:

det⁡(A−λI)=0\det(A - \lambda I) = 0

Since AA is of size n×nn \times n, its characteristic polynomial is of degree nn. By the Fundamental Theorem of Algebra, a polynomial of degree nn has exactly nn roots (including multiplicities).

The algebraic multiplicity of an eigenvalue is the number of times it appears as a root of this characteristic polynomial. Consequently, the maximum possible multiplicity of any single eigenvalue is nn, which occurs when all nn roots of the characteristic polynomial are identical.

Example:

Consider the n×nn \times n identity matrix InI_n. Its characteristic equation is:

det⁡(In−λIn)=(1−λ)n=0\det(I_n - \lambda I_n) = (1 - \lambda)^n = 0

The eigenvalue λ=1\lambda = 1 has a multiplicity of nn.

Thus, the maximum multiplicity of any eigenvalue of an n×nn \times n matrix is nn.

Hence, the correct option is A.

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