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Official PYQ · 2021

GATE CS 2021 Set 2 Q3 — General Aptitude

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If θ\theta is the angle, in degrees, between the longest diagonal of the cube and any one of the edges of the cube, then, cos⁡θ=\cos \theta =

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Answer: B

To find the angle θ\theta between the longest diagonal of a cube and any of its edges, we can place the cube in a 3D Cartesian coordinate system.

Let one vertex of the cube of side length aa be at the origin (0,0,0)(0, 0, 0).

  • The edge along the x-axis can be represented by the vector:
    u⃗=(a,0,0)\vec{u} = (a, 0, 0)
  • The longest diagonal from (0,0,0)(0,0,0) to (a,a,a)(a, a, a) is represented by the vector:
    d⃗=(a,a,a)\vec{d} = (a, a, a)

The cosine of the angle θ\theta between these two vectors is given by the dot product formula:

cos⁡θ=d⃗⋅u⃗∣d⃗∣∣u⃗∣\cos \theta = \frac{\vec{d} \cdot \vec{u}}{|\vec{d}| |\vec{u}|}

Computing the individual terms:

  • d⃗⋅u⃗=(a)(a)+(a)(0)+(a)(0)=a2\vec{d} \cdot \vec{u} = (a)(a) + (a)(0) + (a)(0) = a^2
  • ∣d⃗∣=a2+a2+a2=a3|\vec{d}| = \sqrt{a^2 + a^2 + a^2} = a\sqrt{3}
  • ∣u⃗∣=a2+02+02=a|\vec{u}| = \sqrt{a^2 + 0^2 + 0^2} = a

Substituting these values back into the formula:

cos⁡θ=a2(a3)(a)=13\cos \theta = \frac{a^2}{(a\sqrt{3})(a)} = \frac{1}{\sqrt{3}}

Thus, the correct option is B.

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