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GATE CS 2021 Set 2 Q24 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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Suppose that PP is a 4×54 \times 5 matrix such that every solution of the equation Px=0\text{Px=0} is a scalar multiple of [25431]T\begin{bmatrix} 2 & 5 & 4 &3 & 1 \end{bmatrix}^T. The rank of PP is __________
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Answer: 4 : 4

We are given that PP is a 4×54 \times 5 matrix. The equation Px=0Px = 0 represents a homogeneous system of linear equations.

The set of all solutions to Px=0Px = 0 forms the null space (or kernel) of the matrix PP.

According to the problem, every solution of Px=0Px = 0 is a scalar multiple of the single non-zero vector:

v=[25431]Tv = \begin{bmatrix} 2 & 5 & 4 & 3 & 1 \end{bmatrix}^T

This implies that the null space of PP is spanned by this single vector vv. Since v≠0v \neq 0, the dimension of the null space (known as the nullity of PP) is:

Nullity(P)=1\text{Nullity}(P) = 1

By the Rank-Nullity Theorem, for any m×nm \times n matrix PP:

Rank(P)+Nullity(P)=n\text{Rank}(P) + \text{Nullity}(P) = n

Here, the number of columns n=5n = 5. Substituting the values:

Rank(P)+1=5  ⟹  Rank(P)=4\text{Rank}(P) + 1 = 5 \implies \text{Rank}(P) = 4

Thus, the rank of PP is 4.

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