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GATE CS 1997 Q1.3 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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The determinant of the matrix [6−81102460048000−1]\begin{bmatrix} 6 & -8 & 1 & 1 \\ 0 & 2 & 4 & 6 \\ 0 & 0 & 4 & 8 \\ 0 & 0 & 0 & -1 \end{bmatrix}

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Answer: B

The given matrix is an upper triangular matrix because all elements below the main diagonal are zero:

A=[6−81102460048000−1]A = \begin{bmatrix} 6 & -8 & 1 & 1 \\ 0 & 2 & 4 & 6 \\ 0 & 0 & 4 & 8 \\ 0 & 0 & 0 & -1 \end{bmatrix}

For any upper triangular (or lower triangular) matrix, the determinant is simply the product of its diagonal elements.

The diagonal elements of the matrix AA are 66, 22, 44, and −1-1.

det⁡(A)=6×2×4×(−1)=−48\det(A) = 6 \times 2 \times 4 \times (-1) = -48

Therefore, the correct option is B.

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