GATE CS 2011 Q62 — General Aptitude

To determine which microbe is the most dangerous and should be targeted first, we analyze the three given factors: Toxicity, Potency, and Growth (represented by the area of the circle, $\text{Area} = \frac{\pi}{4} d^2$).

From the given graph, we extract the values for each microbe:

• Microbe P: Toxicity = $400$, Potency = $800$, Diameter = $50$
  $\implies \text{Growth (Area)} \approx 1963.5$
• Microbe Q: Toxicity = $800$, Potency = $600$, Diameter = $10$
  $\implies \text{Growth (Area)} \approx 78.5$
• Microbe R: Toxicity = $600$, Potency = $300$, Diameter = $30$
  $\implies \text{Growth (Area)} \approx 706.9$
• Microbe S: Toxicity = $200$, Potency = $200$, Diameter = $100$
  $\implies \text{Growth (Area)} \approx 7854.0$

The danger to human beings varies proportionately with these three attributes. Microbe S exhibits an exceptionally high growth rate (an area of $7854$, which is nearly $4$ times that of P and over $100$ times that of Q). Due to this massive growth potential within $24$ hours, microbe S poses the most dominant threat to the human immune system.

Thus, the company should target microbe S in its first attempt.