Answer: B
Let the given logarithmic relation be equal to a constant k:
log(P)=21log(Q)=31log(R)=k
Using the property of logarithms alog(x)=log(xa), we can rewrite the terms as:
log(P)=log(Q1/2)=log(R1/3)=k
Taking the antilogarithm on all sides, we get:
P=Q1/2=R1/3
Now, we express Q and R in terms of P:
- Q=P2
- R=P3
Let's verify the given options using these relations:
- Option A: P2=Q3R2⟹P2=(P2)3(P3)2=P12 (False)
- Option B: Q2=PR⟹(P2)2=P⋅P3⟹P4=P4 (True)
- Option C: Q2=R3P⟹(P2)2=(P3)3⋅P⟹P4=P10 (False)
- Option D: R=P2Q2⟹P3=P2(P2)2=P6 (False)
Thus, the correct option is B.