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Official PYQ · 2018

GATE CS 2018 QGA-3 — General Aptitude

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The area of a square is dd. What is the area of the circle which has the diagonal of the square as its diameter?

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Answer: D

Let the side length of the square be aa.

The area of the square is given as:

Area=a2=d\text{Area} = a^2 = d

The length of the diagonal DD of this square is:

D=a2D = a\sqrt{2}

Since the diagonal of the square is the diameter of the circle, the radius rr of the circle is:

r=D2=a22=a2r = \frac{D}{2} = \frac{a\sqrt{2}}{2} = \frac{a}{\sqrt{2}}

Now, the area of the circle is:

Area of circle=πr2=π(a2)2=πa22\text{Area of circle} = \pi r^2 = \pi \left(\frac{a}{\sqrt{2}}\right)^2 = \frac{\pi a^2}{2}

Substituting a2=da^2 = d into the equation:

Area of circle=12πd\text{Area of circle} = \frac{1}{2}\pi d

Therefore, the correct option is D.

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