GATE CS 2014 Set 3 QGA-9 — General Aptitude

Let $M_{2011}$ and $F_{2011}$ represent the number of male and female students in $2011$, and $M_{2012}$ and $F_{2012}$ represent the same for $2012$.

From the given line graph, the ratio of male to female students ($\text{Male}/\text{Female}$) for the respective years is:

• For $2011$: $\frac{M_{2011}}{F_{2011}} = 1.0 \implies M_{2011} = 1.0 \times F_{2011}$
• For $2012$: $\frac{M_{2012}}{F_{2012}} = 1.5 \implies M_{2012} = 1.5 \times F_{2012}$

We are given that the number of female students in both years is equal, i.e., $F_{2011} = F_{2012} = F$.

Substituting this, we get:

Thus, the ratio of male students in $2012$ to male students in $2011$ is $1.5:1$.