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GATE CS 2014 Set 2 Q4 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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If the matrix AA is such that A=[2−47][195]A= \begin{bmatrix} 2\\ −4\\7\end{bmatrix}\begin{bmatrix}1& 9& 5\end{bmatrix} then the determinant of AA is equal to ______.
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The given matrix AA is defined as the product of a column vector and a row vector:

A=[2−47][195]A = \begin{bmatrix} 2\\ −4\\7\end{bmatrix}\begin{bmatrix}1 & 9 & 5\end{bmatrix}

This is an outer product of two vectors, A=uvTA = u v^T, where uu is a 3×13 \times 1 column vector and vTv^T is a 1×31 \times 3 row vector. Thus, AA is a 3×33 \times 3 matrix.

Since AA is formed by multiplying a single column vector by a row vector, every row of AA is a scalar multiple of the row vector vTv^T:

A=[2(1)2(9)2(5)−4(1)−4(9)−4(5)7(1)7(9)7(5)]=[21810−4−36−2076335]A = \begin{bmatrix} 2(1) & 2(9) & 2(5) \\ -4(1) & -4(9) & -4(5) \\ 7(1) & 7(9) & 7(5) \end{bmatrix} = \begin{bmatrix} 2 & 18 & 10 \\ -4 & -36 & -20 \\ 7 & 63 & 35 \end{bmatrix}

Because all rows are linearly dependent, the rank of AA is 11. For any n×nn \times n matrix with n≥2n \ge 2, if its rank is strictly less than nn, the matrix is singular, and its determinant is zero.

Therefore, the determinant of AA is 0.

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