Official PYQ · 2014Set 2 · QGA-9NAT1 mark

GATE CS 2014 Set 2 QGA-9 — General Aptitude

The ratio of male to female students in a college for five years is plotted in the following line graph. If the number of female students doubled in $2009$ , by what percent did the number of male students increase in $2009$ ?

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Answer: 140

From the given line graph, we can find the ratio of male to female students ( $\text{Ratio} = \frac{\text{Male}}{\text{Female}}$ ) for the years 2008 and 2009:

Ratio in 2008 ( $R_{2008}$ ) = $1.25$
Ratio in 2009 ( $R_{2009}$ ) = $1.5$

Let the number of female students in 2008 be $F$ .

Using the ratio for 2008:

\frac{M_{2008}}{F_{2008}} = 1.25 \implies M_{2008} = 1.25 \times F

In 2009, the number of female students doubled. Therefore:

F_{2009} = 2F

Using the ratio for 2009:

\frac{M_{2009}}{F_{2009}} = 1.5 \implies M_{2009} = 1.5 \times (2F) = 3F

Now, we calculate the percentage increase in the number of male students from 2008 to 2009:

\text{Percentage Increase} = \left( \frac{M_{2009} - M_{2008}}{M_{2008}} \right) \times 100

\text{Percentage Increase} = \left( \frac{3F - 1.25F}{1.25F} \right) \times 100

\text{Percentage Increase} = \frac{1.75}{1.25} \times 100 = 1.4 \times 100 = 140\%

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Published 10 Oct 2026

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