Answer: D
Given the equation:
∣x2−2x+3∣=11
Since x is a real number, we analyze the two possible cases for the absolute value:
Case 1: x2−2x+3=11
x2−2x−8=0
(x−4)(x+2)=0
This gives the real roots:
x=4orx=−2
Case 2: x2−2x+3=−11
x2−2x+14=0
The discriminant of this quadratic equation is:
D=(−2)2−4(1)(14)=4−56=−52<0
Since the discriminant is negative, there are no real roots in this case.
Thus, the only possible real values for x are x=4 and x=−2.
Now, we evaluate the expression E=∣−x3+x2−x∣ for these values of x:
- For x=4:
E=∣−(4)3+(4)2−4∣=∣−64+16−4∣=∣−52∣=52
- For x=−2:
E=∣−(−2)3+(−2)2−(−2)∣=∣8+4+2∣=∣14∣=14
Therefore, the possible values of ∣−x3+x2−x∣ are 14 and 52.