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Official PYQ · 2014

GATE CS 2014 Set 2 QGA-8 — General Aptitude

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If xx is real and ∣x2−2x+3∣=11\mid x^2-2x+3 \mid = 11, then possible values of ∣−x3+x2−x∣\mid -x^3+x^2-x\mid include

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Answer: D

Given the equation:

∣x2−2x+3∣=11|x^2 - 2x + 3| = 11

Since xx is a real number, we analyze the two possible cases for the absolute value:

Case 1: x2−2x+3=11x^2 - 2x + 3 = 11

x2−2x−8=0x^2 - 2x - 8 = 0 (x−4)(x+2)=0(x - 4)(x + 2) = 0

This gives the real roots:

x=4orx=−2x = 4 \quad \text{or} \quad x = -2

Case 2: x2−2x+3=−11x^2 - 2x + 3 = -11

x2−2x+14=0x^2 - 2x + 14 = 0

The discriminant of this quadratic equation is:

D=(−2)2−4(1)(14)=4−56=−52<0D = (-2)^2 - 4(1)(14) = 4 - 56 = -52 < 0

Since the discriminant is negative, there are no real roots in this case.

Thus, the only possible real values for xx are x=4x = 4 and x=−2x = -2.

Now, we evaluate the expression E=∣−x3+x2−x∣E = |-x^3 + x^2 - x| for these values of xx:

  • For x=4x = 4: E=∣−(4)3+(4)2−4∣=∣−64+16−4∣=∣−52∣=52E = |-(4)^3 + (4)^2 - 4| = |-64 + 16 - 4| = |-52| = 52
  • For x=−2x = -2: E=∣−(−2)3+(−2)2−(−2)∣=∣8+4+2∣=∣14∣=14E = |-(-2)^3 + (-2)^2 - (-2)| = |8 + 4 + 2| = |14| = 14

Therefore, the possible values of ∣−x3+x2−x∣|-x^3 + x^2 - x| are 1414 and 5252.

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