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GATE CS 2014 Set 1 Q4 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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Consider the following system of equations:  

  • 3x+2y=13x + 2y = 1
  • 4x+7z=14x + 7z = 1
  • x+y+z=3x + y + z = 3
  • x−2y+7z=0x - 2y + 7z = 0

The number of solutions for this system is ______________

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Answer: 1

To find the number of solutions for the given system of linear equations, we can solve a subset of the equations and check if the solution satisfies the remaining equation.

The system of equations is:

  1. 3x+2y=13x + 2y = 1
  2. 4x+7z=14x + 7z = 1
  3. x+y+z=3x + y + z = 3
  4. x−2y+7z=0x - 2y + 7z = 0

Let's find a candidate solution using equations (1), (2), and (3):

From equation (3), express zz in terms of xx and yy:

z=3−x−yz = 3 - x - y

Substitute zz into equation (2):

4x+7(3−x−y)=14x + 7(3 - x - y) = 1 4x+21−7x−7y=14x + 21 - 7x - 7y = 1 −3x−7y=−20  ⟹  3x+7y=20— (5)-3x - 7y = -20 \implies 3x + 7y = 20 \quad \text{--- (5)}

Now, subtract equation (1) from equation (5):

(3x+7y)−(3x+2y)=20−1(3x + 7y) - (3x + 2y) = 20 - 1 5y=19  ⟹  y=3.85y = 19 \implies y = 3.8

Substitute y=3.8y = 3.8 back into equation (1):

3x+2(3.8)=13x + 2(3.8) = 1 3x+7.6=1  ⟹  3x=−6.6  ⟹  x=−2.23x + 7.6 = 1 \implies 3x = -6.6 \implies x = -2.2

Now, find zz using equation (3):

z=3−(−2.2)−3.8=1.4z = 3 - (-2.2) - 3.8 = 1.4

So, the unique candidate solution is (x,y,z)=(−2.2,3.8,1.4)(x, y, z) = (-2.2, 3.8, 1.4).

Let's verify if this candidate solution satisfies the remaining equation (4):

x−2y+7z=−2.2−2(3.8)+7(1.4)x - 2y + 7z = -2.2 - 2(3.8) + 7(1.4) =−2.2−7.6+9.8= -2.2 - 7.6 + 9.8 =−9.8+9.8=0= -9.8 + 9.8 = 0

Since the candidate solution satisfies all four equations, the system is consistent and has exactly 1 unique solution.

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