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GATE CS 2013 Q3 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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Which one of the following does NOT equal ∣1xx21yy21zz2∣?\begin{vmatrix} 1 & x & x^{2}\\ 1& y & y^{2}\\ 1 & z & z^{2} \end{vmatrix} \quad ?

Choose one option
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Answer: A

Let the given determinant be D=∣1xx21yy21zz2∣D = \begin{vmatrix} 1 & x & x^{2}\\ 1& y & y^{2}\\ 1 & z & z^{2} \end{vmatrix}. We can test the options using elementary column and row operations.

Testing Option A:

DA=∣1x(x+1)x+11y(y+1)y+11z(z+1)z+1∣D_A = \begin{vmatrix} 1& x(x+1)& x+1\\ 1& y(y+1) & y+1\\ 1& z(z+1) & z+1 \end{vmatrix}

Apply the column operation C2←C2−C3C_2 \leftarrow C_2 - C_3:

DA=∣1x2−1x+11y2−1y+11z2−1z+1∣D_A = \begin{vmatrix} 1& x^2-1 & x+1\\ 1& y^2-1 & y+1\\ 1& z^2-1 & z+1 \end{vmatrix}

Apply C2←C2+C1C_2 \leftarrow C_2 + C_1 followed by C3←C3−C1C_3 \leftarrow C_3 - C_1:

DA=∣1x2x1y2y1z2z∣D_A = \begin{vmatrix} 1& x^2 & x\\ 1& y^2 & y\\ 1& z^2 & z \end{vmatrix}

Interchanging columns C2C_2 and C3C_3 introduces a negative sign:

DA=−∣1xx21yy21zz2∣=−DD_A = -\begin{vmatrix} 1& x & x^2\\ 1& y & y^2\\ 1& z & z^2 \end{vmatrix} = -D

Since DA=−DD_A = -D, Option A does not equal the original determinant DD (unless D=0D = 0).

Verifying Option B:
Applying C2←C2−C1C_2 \leftarrow C_2 - C_1 and C3←C3−C1C_3 \leftarrow C_3 - C_1 on Option B directly yields DD.

Verifying Option C:
Applying row operations R1←R1−R2R_1 \leftarrow R_1 - R_2 and R2←R2−R3R_2 \leftarrow R_2 - R_3 on the original determinant DD yields Option C, preserving the determinant value.

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