Let be real valued square symmetric matrix of rank with Consider the following statements.
- One eigenvalue must be in
- The eigenvalue with the largest magnitude must be strictly greater than
Which of the above statements about eigenvalues of is/are necessarily CORRECT?
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Answer: B
For any real symmetric matrix , the sum of the squares of its elements is equal to the sum of the squares of its eigenvalues (this is the square of the Frobenius norm, denoted as ):
Since the rank of is , there are exactly two non-zero eigenvalues, say and . All other eigenvalues are . Therefore, we have:
Let us evaluate the given statements:
Statement I: One eigenvalue must be in
Suppose, for contradiction, that no eigenvalue lies in . Since all other eigenvalues are (which lies in ), this assumption requires both non-zero eigenvalues to satisfy:
Squaring both inequalities:
Adding them gives:
This directly contradicts our condition . Thus, at least one eigenvalue must lie in the interval .
Statement I is necessarily CORRECT.
Statement II: The eigenvalue with the largest magnitude must be strictly greater than
Consider the case where and . Here:
The magnitude of both eigenvalues is . The largest magnitude is , which is not strictly greater than . Since we found a valid counterexample, Statement II is not necessarily correct.
Thus, only Statement I is necessarily correct.
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