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GATE CS 2017 Set 1 Q30 — Linear Algebra: Matrices, Determinants, System of Linear Equations

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Let uu and vv be two vectors in R2\mathbf{R}^{2} whose Euclidean norms satisfy ∥u∥=2∥v∥\left \| u \right \| = 2\left \| v \right \|. What is the value of α\alpha such that w=u+αvw = u + \alpha v bisects the angle between uu and vv?

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Answer: A

An elegant way to solve this is using unit vectors.

Let u^\hat{u} and v^\hat{v} be the unit vectors in the directions of uu and vv respectively:

u^=u∥u∥andv^=v∥v∥\hat{u} = \frac{u}{\|u\|} \quad \text{and} \quad \hat{v} = \frac{v}{\|v\|}

The vector that bisects the angle between uu and vv must point in the direction of the sum of their unit vectors, i.e., it must be a positive scalar multiple of (u^+v^)(\hat{u} + \hat{v}):

w=c(u^+v^)for some c>0w = c(\hat{u} + \hat{v}) \quad \text{for some } c > 0

We are given that the Euclidean norms satisfy ∥u∥=2∥v∥\|u\| = 2\|v\|. Therefore, we can express uu and vv as:

u=∥u∥u^=2∥v∥u^u = \|u\|\hat{u} = 2\|v\|\hat{u} v=∥v∥v^v = \|v\|\hat{v}

Substitute these into the given expression for ww:

w=u+αvw = u + \alpha v w=2∥v∥u^+α∥v∥v^w = 2\|v\|\hat{u} + \alpha \|v\|\hat{v} w=∥v∥(2u^+αv^)w = \|v\| (2\hat{u} + \alpha\hat{v})

For ww to bisect the angle between uu and vv, it must be a scalar multiple of (u^+v^)(\hat{u} + \hat{v}). This requires the coefficients of u^\hat{u} and v^\hat{v} to be equal:

2=α2 = \alpha

Thus, α=2\alpha = 2.

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