Consider the first order initial value problem y’=y+2x−x2,y(0)=1,(0≤x<∞) with exact solution y(x)=x2+ex. For x=0.1, the percentage difference between the exact solution and the solution obtained using a single iteration of the second-order Runga-Kutta method with step-size h=0.1 is _______View answerShowHide
Answer: 0.060:0.063
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