Consider the function g(t)=e−tsin(2πt)u(t)g(t) = e^{-t}\sin(2\pi t)u(t)g(t)=e−tsin(2πt)u(t) where u(t)u(t)u(t) is the unit step function. The area under g(t)g(t)g(t) is ______.Your numerical answerSubmitTry againView answerShowHideAnswer: 0.14:0.16Worked explanation not available yet.Free practice · Your answers on this page are not saved.