Let f(z)=az+bcz+d.f(z)=\dfrac{az+b}{cz+d}.f(z)=cz+daz+b. If f(z1)=f(z2)f(z_{1})=f(z_{2})f(z1)=f(z2) for all z1≠z2,a=2,b=4z_{1}\neq z_{2},a=2,b=4z1=z2,a=2,b=4 and c=5,c=5,c=5, then ddd should be equal to ________.Your numerical answerSubmitTry againView answerShowHideAnswer: 9.9:10.1Worked explanation not available yet.Free practice · Your answers on this page are not saved.