With initial values y(0)=y’(0)=1y(0) =y’(0)=1y(0)=y’(0)=1, the solution of the differential equation d2ydx2+4dydx+4y=0\frac{d^2y}{dx^2}+4 \frac{dy}{dx}+4y=0dx2d2y+4dxdy+4y=0 at x=1x=1x=1 is ________Your numerical answerSubmitTry againView answerShowHideAnswer: 0.53:0.55Worked explanation not available yet.Free practice · Your answers on this page are not saved.