If z=xy ln(xy)z= xy \text{ ln} (xy)z=xy ln(xy), thenChoose one optionAx∂z∂x+y∂z∂y=0x\frac{\partial z}{\partial x}+y\frac{\partial z}{\partial y}= 0 \\x∂x∂z+y∂y∂z=0By∂z∂x=x∂z∂yy\frac{\partial z}{\partial x}= x\frac{\partial z}{\partial y} \\y∂x∂z=x∂y∂zCx∂z∂x=y∂z∂yx\frac{\partial z}{\partial x}= y\frac{\partial z}{\partial y} \\x∂x∂z=y∂y∂zDy∂z∂x+x∂z∂y=0y\frac{\partial z}{\partial x}+x\frac{\partial z}{\partial y}= 0y∂x∂z+x∂y∂z=0Submit50:50Try againView answerShowHideAnswer: CWorked explanation not available yet.Free practice · Your answers on this page are not saved.